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Anti-derivative
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April 1st, 2006 23:57 #1 |
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tomzx user |
Here's the equation: One of my friend had this problem and I didn't want to take too much time on it. Have fun. ______________________ Techno-Science |
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April 2nd, 2006 12:41 #2 |
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robert_ak |
Quoting tomzx: Use: u = sin(4x) dv = e^(2x)dx dv= 4cos(4x)dx v = .5*e^(2x) Do: uv - INT[v du] You will get something with cos(4x). Redo the substitution: u = cos(4x) dv = e^(2x)dx dv= -4sin(4x)dx v = .5*e^(2x) Do: uv - INT[v du] again You will get the terms "INT[e^(2x)*sin(4x)]dx" on both sides of the equation: isolate and you will get the answer. I'll try writing the whole solution here soon. It should give you: -1/5*e^(2x)*cos(4x)+1/10*e^(2x)*sin(4x) ______________________ hai |
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April 2nd, 2006 14:08 #3 |
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3hirty6ix |
O BOY integration by parts ______________________ o hi dere |
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April 3rd, 2006 22:30 #4 |
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damaged |
what is all this 
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April 3rd, 2006 22:52 #5 |
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robert_ak |
Quoting damaged:integral calculus 
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April 6th, 2006 23:40 #6 |
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ga__S |
i can't see the function 
______________________ heh |
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April 7th, 2006 18:05 #7 |
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tomzx user |
thx, but a bit late, found out myself 
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April 7th, 2006 20:29 #8 |
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ga__S |
What about this one? I dunno if it will stay on their website but.. ______________________ heh |
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April 9th, 2006 10:21 #9 |
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3hirty6ix |
cant see shit captain
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